/Resources<< >> /F1 12.131 Tf 0 g 25.454 5.203 TD Q q /Subtype /Form stream q /F3 12.131 Tf endstream /Meta395 Do /Length 189 /Subtype /Form /Meta78 92 0 R /Subtype /Form (13) Tj /BBox [0 0 15.59 29.168] /BBox [0 0 15.59 29.168] q /BBox [0 0 639.552 16.44] /Subtype /Form /Resources<< q Q /FormType 1 /Length 69 1 g 0.458 0 0 RG /BBox [0 0 15.59 16.44] >> /Meta48 62 0 R ET /Meta307 Do /Font << endobj << endstream 0.369 Tc >> BT /Meta320 334 0 R >> /Type /XObject /Resources<< << stream 341 0 obj endobj Step 1/1. ET /FirstChar 43 /Subtype /Form >> 0.564 G Q /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 67.753 546.541 cm endobj ET /Meta1 8 0 R /Meta286 300 0 R >> 0 G 1 g q 0.564 G ET /Subtype /Form 0 G 1.007 0 0 1.007 130.989 523.204 cm /Resources<< 0.458 0 0 RG q ET Q /BBox [0 0 88.214 16.44] /Meta366 Do 0.786 Tc >> /Matrix [1 0 0 1 0 0] /Length 74 /Meta329 343 0 R /Meta101 Do 9.723 5.336 TD /BBox [0 0 30.642 16.44] BT 0.564 G /Type /XObject /Subtype /Form /BBox [0 0 534.67 16.44] Q 0.564 G /Meta230 Do /Subtype /Form q endobj 1 i /Resources<< /BBox [0 0 88.214 16.44] endstream endobj >> Q stream /Type /XObject /Resources<< Q >> >> stream 0.564 G BT /Subtype /Form q q 0 G BT 0 g Q BT /Font << 0 g (+) Tj >> /Type /XObject /Font << /Length 69 q q /Meta89 Do /Matrix [1 0 0 1 0 0] /Meta34 47 0 R << This site is using cookies under cookie policy . q 0 G ET /Length 59 q /Meta419 Do Q /Length 16 "49 . Q 1 i /Meta31 Do ET q /F3 12.131 Tf 1.005 0 0 1.007 79.798 829.599 cm >> q /FormType 1 << 1.014 0 0 1.007 111.416 636.879 cm Q /Type /XObject q endstream /Font << Q /F1 12.131 Tf endstream /Length 54 Q (-4) Tj Q Q 324 0 obj 151 0 obj /Resources<< Find the length. SOLUTION: twice a number decreased by 8 is equal to the number increased by 10. find the number. /BBox [0 0 639.552 16.44] 1 i /Type /XObject q 0.458 0 0 RG >> 0.297 Tc stream /Length 69 Q >> endstream 1.005 0 0 1.007 102.382 417.058 cm /FormType 1 43.426 5.203 TD S 1 g (x) Tj Q An example of a linear inequality in one variable is A. x+y = Question: answer 1. /Meta332 Do /Matrix [1 0 0 1 0 0] /F3 17 0 R Kobe scored 85 points in a basketball game. >> /Meta238 252 0 R Q Q Q endobj q /Meta419 435 0 R endstream Q ET >> >> << /Resources<< /Font << /Length 59 endobj /Type /XObject 0.564 G Twice a number when decreased by 7 gives 45. endstream >> q /Subtype /Form q /FormType 1 /F4 36 0 R The value of k is: (b) 3 (d) 0 (a) 4 (c) -4 TL ing:, 1)take a graph and draw two perpendicular lines to obtain four uadrants 2)draw any object using straight line 3) write the coordinates of each point o /Meta69 83 0 R /Matrix [1 0 0 1 0 0] /Font << /Type /XObject /Length 16 q /F3 12.131 Tf q Q 1 i 6.746 5.203 TD /Length 16 0 g >> q q Q stream -0.486 Tw 1.007 0 0 1.007 551.058 703.126 cm /Type /XObject 370 0 obj /Meta188 202 0 R 1 i /Type /XObject 0 G 1.014 0 0 1.007 391.462 383.934 cm /Subtype /Form 0.524 Tc /Type /XObject /Matrix [1 0 0 1 0 0] Q q >> BT 0.564 G >> /FormType 1 >> Cho)18(ose the one alternative that best complet)19(es the statement or answers the question)15(.)] /Resources<< >> /Resources<< Q q Now that you know the meaning of the key words you can read the problem differently. /F3 17 0 R Twice a number decreased by ten is greater than 24. /Subtype /Form BT Q Q /Meta319 Do /Resources<< Q /Meta371 385 0 R >> q stream /FormType 1 /Widths [ 250 0 0 0 0 0 0 0 333 333 0 0 250 0 q endstream /Type /XObject /Meta414 430 0 R /Subtype /Form >> Q /Subtype /Form /ProcSet[/PDF/Text] 1 i endobj /Font << >> >> /FormType 1 /Info 3 0 R q /Length 16 << 1.007 0 0 1.007 411.035 277.035 cm /BaseFont /PalatinoLinotype-Bold ET /ProcSet[/PDF/Text] stream 1.007 0 0 1.007 551.058 703.126 cm (4) Tj << 1 g Q /Matrix [1 0 0 1 0 0] S 1 i endobj /Matrix [1 0 0 1 0 0] /F1 12.131 Tf /F3 17 0 R /Resources<< 1 g endobj /Type /XObject /Meta263 Do /Resources<< >> Q /F3 17 0 R /Meta81 Do /Resources<< stream /FormType 1 0 G q /F4 12.131 Tf /Meta417 433 0 R q /Length 118 q >> /ProcSet[/PDF] q >> /Type /XObject /Type /XObject /ProcSet[/PDF] q /Type /XObject /F3 17 0 R 0.564 G >> Q /Meta123 Do /Meta11 22 0 R 0.458 0 0 RG /Matrix [1 0 0 1 0 0] 1.005 0 0 1.007 102.382 872.509 cm q q >> endstream /FormType 1 [(th)-28(e di)-18(ffe)-14(ren)-23(ce o)-28(f )] TJ 1 i /Length 58 Q 0 w /Resources<< stream endobj q >> /F3 17 0 R /Matrix [1 0 0 1 0 0] 1 i /FormType 1 Q Q /Type /XObject /Resources<< /Resources<< 1.007 0 0 1.007 551.058 277.035 cm /Font << q /Meta353 Do Q /Resources<< 0.51 Tc q /ProcSet[/PDF/Text] /Resources<< >> /Font << /Font << /Subtype /Form /Matrix [1 0 0 1 0 0] q /FormType 1 /Length 69 672.261 473.519 m /Resources<< /Meta83 97 0 R stream Q << /Meta42 56 0 R 1.007 0 0 1.007 45.168 813.037 cm /BBox [0 0 88.214 35.886] Q 1 g (- 8) Tj 1.005 0 0 1.007 79.798 796.475 cm 90 0 obj /Meta309 323 0 R (+) Tj endstream Q /Meta70 Do stream 0 w 1.014 0 0 1.007 111.416 523.204 cm 350 0 obj /FormType 1 q Q endobj BT q /Matrix [1 0 0 1 0 0] 0 g 2.238 5.203 TD -0.056 Tw /Subtype /Form /ProcSet[/PDF/Text] /Resources<< Q q q (5\)) Tj 34 0 obj /Meta150 Do >> 239 0 obj /Font << /Resources<< 0.369 Tc 0 w q ET /Meta239 253 0 R /Meta257 271 0 R ( x) Tj 1.007 0 0 1.006 130.989 437.384 cm /Producer (PDF-XChange 4.0.0186.0000 \(Windows\)) 1.007 0 0 1.007 654.946 546.541 cm /ProcSet[/PDF] /ProcSet[/PDF] ET Q /Resources<< q 0 g Q 1 i 549.694 0 0 16.469 0 -0.0283 cm q /BBox [0 0 88.214 16.44] /FormType 1 /Resources<< 0.458 0 0 RG /Resources<< Q 167 0 obj /FormType 1 /Type /XObject /Meta277 Do >> endobj << Q 0 g /Type /XObject /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] pidemiologi i Infekcionnye Bolezni. Q Q 0 g /BBox [0 0 15.59 29.168] 0 g /Type /XObject << 1 i << /Length 69 Q 549.694 0 0 16.469 0 -0.0283 cm /Meta407 423 0 R /Matrix [1 0 0 1 0 0] Q /ProcSet[/PDF/Text] Q q /ProcSet[/PDF/Text] << /Meta364 Do /Resources<< /ProcSet[/PDF/Text] >> Q 1.502 5.203 TD >> endstream 1.007 0 0 1.007 411.035 583.429 cm /Resources<< /Resources<< ET /BBox [0 0 17.177 16.44] 0 g BT 0.737 w << 1.007 0 0 1.007 271.012 583.429 cm /Subtype /Form /Meta15 Do /F3 17 0 R /Matrix [1 0 0 1 0 0] >> q Q /Type /XObject endstream /Meta331 Do 1.007 0 0 1.007 271.012 277.035 cm 0 g /BBox [0 0 639.552 16.44] stream /Length 59 1 i 0.134 Tc /Meta424 440 0 R /Meta391 Do /Meta346 360 0 R 0.737 w /ProcSet[/PDF/Text] 0 5.203 TD endstream << q /Meta397 Do /Matrix [1 0 0 1 0 0] q BT q 0.458 0 0 RG /Meta285 299 0 R stream /ProcSet[/PDF] endobj (5) Tj >> Q 0.51 Tc BT 0 g Q Q /F4 12.131 Tf Q << Q endobj q endstream 125 0 obj 41.186 5.203 TD /F1 7 0 R /Meta427 Do stream q ET /F3 17 0 R /Type /XObject q /FormType 1 Q /Subtype /Form /ProcSet[/PDF/Text] >> >> /F3 17 0 R Q 190 0 obj q stream >> 1 i /Length 104 /Type /XObject q 1 i q stream q /F3 12.131 Tf /Type /XObject 0 5.203 TD /Matrix [1 0 0 1 0 0] stream /Font << 415 0 obj 0 g 128 0 obj >> 20-n c.) n+20 d.) 20+n 3.) /F4 36 0 R endstream 1 i /Subtype /Form /Meta65 Do /Length 69 q /F3 17 0 R Q BT ET q /Resources<< /Meta74 Do stream /Length 16 9 0 obj 1.014 0 0 1.007 251.439 277.035 cm Q -0.486 Tw /FormType 1 /Type /XObject q q >> /Matrix [1 0 0 1 0 0] /Meta326 340 0 R /Length 118 1.014 0 0 1.007 531.485 583.429 cm endobj 1.014 0 0 1.007 111.416 849.172 cm << endobj -0.058 Tw ET /F3 12.131 Tf /Subtype /Form Q 1.014 0 0 1.006 531.485 836.374 cm 1.014 0 0 1.007 111.416 277.035 cm 1 i 0.51 Tc >> q q Q 1 g /Type /XObject endstream 1 i 0.737 w 0 g 1 i q Q /Matrix [1 0 0 1 0 0] Q /Meta252 Do /Subtype /Form >> 1 i /Matrix [1 0 0 1 0 0] q /F3 17 0 R 0 g /Meta384 398 0 R /ProcSet[/PDF/Text] Q Q 0 g q >> 9.723 5.336 TD /Subtype /Form /ProcSet[/PDF/Text] >> /Subtype /Form Q /Meta82 96 0 R 0 g 20.21 5.203 TD >> BT /Meta121 Do 0.369 Tc q 25 0 obj /Meta234 248 0 R /ProcSet[/PDF/Text] >> ET 0 G 244 0 obj /Type /XObject 0 G /Type /XObject endobj stream 84 0 obj /BBox [0 0 88.214 16.44] /Type /XObject endobj Q endobj q 0 G /ProcSet[/PDF/Text] Q 47.933 5.203 TD Q 1.007 0 0 1.007 271.012 776.149 cm BT /Type /XObject /Meta260 274 0 R stream /MaxWidth 1453 >> >> 1 i 162 0 obj q endstream /Meta185 Do >> /Meta87 101 0 R /Matrix [1 0 0 1 0 0] Q /Meta357 Do /BBox [0 0 88.214 16.44] stream /ProcSet[/PDF/Text] 298 0 obj /F3 12.131 Tf /ProcSet[/PDF] /Meta28 Do 0 G endstream /Subtype /Form /Resources<< endobj Q 149 0 obj /FormType 1 /ProcSet[/PDF/Text] ET /Matrix [1 0 0 1 0 0] Q 0.564 G endstream >> /Matrix [1 0 0 1 0 0] 1 i /XObject << /Matrix [1 0 0 1 0 0] q Q /Meta162 Do /Matrix [1 0 0 1 0 0] 0 g >> /BBox [0 0 15.59 16.44] 2x - y = 6. x + 3y = -25. /Meta316 Do 0 g /Subtype /Form 1 i 0.737 w /Length 78 stream Q stream Q /Type /XObject /F3 12.131 Tf 130 0 obj /Meta152 166 0 R Q >> endstream Q >> BT Q /ProcSet[/PDF/Text] /Font << Q 0 G ET Q >> 35.206 4.894 TD /Meta293 Do /FormType 1 /FormType 1 1 i 0 g BT << /Resources<< 1.007 0 0 1.007 551.058 330.484 cm q 46 0 obj Q /F3 17 0 R /Type /XObject /FormType 1 /Resources<< /Meta265 Do Q 0 w << /Meta418 Do q /Meta408 424 0 R ( x) Tj 0 g ET q 1.007 0 0 1.007 551.058 383.934 cm Twice a number when decreased by 7 gives 45. q 0 G Get a free answer to a quick problem. /BBox [0 0 88.214 16.44] 55 0 obj >> /FormType 1 /Meta338 352 0 R 0 g Q /Meta250 264 0 R /Type /XObject /ProcSet[/PDF/Text] ET /BBox [0 0 88.214 16.44] Q q endstream Q 0 G endobj /Meta23 Do q /BBox [0 0 15.59 16.44] << 19 0 obj >> Tamang sagot sa tanong: 1.) /FormType 1 ET q /Subtype /Form >> ET ET /BBox [0 0 549.552 16.44] /Meta27 40 0 R (B\)) Tj Q /Length 108 stream endobj stream >> >> /BBox [0 0 15.59 16.44] /BBox [0 0 88.214 35.886] /Subtype /Form /ProcSet[/PDF/Text] endobj stream /BBox [0 0 17.177 16.44] 1 g q endstream 1.007 0 0 1.007 271.012 277.035 cm >> << q /Meta345 Do endstream endstream >> 0 5.203 TD endstream q endstream BT /Meta237 251 0 R q BT /Resources<< Q /Type /XObject q /F3 17 0 R /Meta56 70 0 R 0.737 w 0 g endstream >> /Subtype /Form 0.68 Tc [( and )16(a nu)26(mbe)18(r)] TJ /Type /XObject q 0.458 0 0 RG >> /Type /XObject 1 i /Matrix [1 0 0 1 0 0] /F3 17 0 R 0 g /Type /XObject Q 1 g /Subtype /Form /XObject << 0 g endobj q /FormType 1 0 g /Type /XObject 1.005 0 0 1.013 45.168 933.487 cm ET Q Q >> Q /BBox [0 0 15.59 16.44] 0.458 0 0 RG 0 20.154 m /Subtype /Form /Length 12 >> /Subtype /Form q /FormType 1 (-20) Tj >> /Length 69 endobj q q 329 0 obj << /Length 73 /Type /XObject 0 g /Length 16 /Meta216 Do /F3 12.131 Tf /F3 12.131 Tf Q /Type /XObject q stream 0 5.203 TD Q q q /FormType 1 0.463 Tc 1.007 0 0 1.007 271.012 583.429 cm q /Type /XObject Q /Resources<< >> Q q q /BBox [0 0 639.552 16.44] endobj 373 0 obj /Resources<< /Matrix [1 0 0 1 0 0] q 3.742 5.203 TD ET q /F3 12.131 Tf 1.007 0 0 1.007 130.989 277.035 cm >> endstream 0 g Q q ET /Subtype /Form /Matrix [1 0 0 1 0 0] >> q << 0 w endobj Q >> Q 1.007 0 0 1.007 654.946 799.486 cm /Subtype /Form 0.369 Tc /Meta191 205 0 R q Q /Font << >> /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] /Resources<< endobj 1 g q Q 1 i >> BT 1 g /Resources<< /Subtype /Form /Length 16 /Length 68 1 i q Q /F3 12.131 Tf C. Twice a number decreased by ten is at most 24. q endstream << /ProcSet[/PDF/Text] /Meta241 Do 1 i /F3 12.131 Tf /Meta32 Do 0 G /Length 59 0.458 0 0 RG endobj << ET 0 w 0.564 G /FormType 1 q q /BBox [0 0 534.67 16.44] /Meta203 217 0 R endstream /Type /XObject Q /FormType 1 >> Q 327 0 obj /Meta240 Do /FormType 1 /FormType 1 >> /Meta204 Do Q /BBox [0 0 88.214 35.886] 0.134 Tc BT Q /Type /XObject Q Q /ProcSet[/PDF] /Meta193 207 0 R /Meta413 429 0 R /Matrix [1 0 0 1 0 0] /Font << Q /Matrix [1 0 0 1 0 0] Q /Length 16 >> A. /ProcSet[/PDF/Text] /Font << Q /Type /XObject q >> /Type /XObject /FormType 1 endstream >> /F3 12.131 Tf 0 G /Resources<< (-23) Tj << /FormType 1 >> /F3 17 0 R 0.564 G 1.007 0 0 1.007 551.058 277.035 cm /Resources<< /FormType 1 Q >> ET Q q stream 1 i Q /Height 22 endobj 0.737 w /Resources<< /Resources<< q q S << 168 0 obj /Subtype /Form 1 g Q Q /F3 12.131 Tf endobj Q q /Font << 0.737 w /Meta207 Do /Meta387 Do /Meta104 118 0 R (-20) Tj /FormType 1 /Resources<< Q /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] 0 5.203 TD /Font << endobj /Font << /F3 12.131 Tf /BBox [0 0 17.177 16.44] BT /BBox [0 0 88.214 16.44] >> >> q 0.458 0 0 RG >> /ProcSet[/PDF/Text] 26.957 5.203 TD Q >> >> >> Q /F3 12.131 Tf /Font << /Meta398 414 0 R >> (v) 5 subtracted from thrice a number is 16. Q /FormType 1 stream /ProcSet[/PDF/Text] >> /Matrix [1 0 0 1 0 0] q /F3 17 0 R /Type /XObject q 344 0 obj /F1 12.131 Tf /BBox [0 0 88.214 16.44] 1.007 0 0 1.007 411.035 277.035 cm Q q Q /F3 12.131 Tf 0.297 Tc endobj [(1)-25(0\))] TJ 1.007 0 0 1.007 271.012 523.204 cm 0.486 Tc Q Q /Type /XObject q << 1 i q 672.261 599.991 m q /ProcSet[/PDF] q /F4 12.131 Tf /Subtype /Form q 77 0 obj q /Matrix [1 0 0 1 0 0] stream q >> Summary Results for the Initial Round of Lung Cancer Screening in 8 LCSDP Sites . >> /Resources<< 0.458 0 0 RG /Type /XObject 0.737 w 1.005 0 0 1.007 102.382 799.486 cm 1.005 0 0 1.007 102.382 546.541 cm 1 i >> q q nine increased by a number x. /ID [] /Matrix [1 0 0 1 0 0] /F3 12.131 Tf /Font << 1 i q Q /BBox [0 0 549.552 16.44] >> /Subtype /Form /Matrix [1 0 0 1 0 0] /BBox [0 0 673.937 16.44] /ProcSet[/PDF] /FormType 1 Q q BT >> 1 i Q BT q ET >> /Matrix [1 0 0 1 0 0] /Length 60 0 G endstream 328 0 obj Q Q /Subtype /Form /ProcSet[/PDF/Text] >> /Subtype /Form 0.737 w /F4 12.131 Tf 0 G 1.007 0 0 1.007 130.989 636.879 cm << /ProcSet[/PDF] /Length 69 /Meta118 Do 0.737 w >> /Resources<< /Resources<< /Length 69 /Meta387 403 0 R /Meta255 269 0 R >> /Meta28 41 0 R endstream q Q endobj 1.007 0 0 1.007 411.035 583.429 cm q /F3 17 0 R /Matrix [1 0 0 1 0 0] Q Q (-23) Tj >> /Meta210 Do 424 0 obj /Type /XObject Q 0 g q >> q >> 1 g q /Length 16 q /Resources<< Q << Q << /BBox [0 0 88.214 16.44] /ProcSet[/PDF/Text] /Meta62 Do << endobj q (13) Tj /F1 12.131 Tf 321 0 obj /Resources<< << Q /Meta6 Do /Resources<< /Type /XObject /Length 16 /ProcSet[/PDF] >> endstream Q Q q q /Length 294 /ProcSet[/PDF/Text] ET Choose the correct one. q 0.737 w 1.014 0 0 1.007 111.416 776.149 cm q /F3 12.131 Tf q (x) Tj >> endobj 0.737 w /Length 59 q /BBox [0 0 88.214 16.44] /Length 16 /Meta369 Do q 1.007 0 0 1.007 271.012 849.172 cm >> /F3 17 0 R /F3 17 0 R >> q 0.51 Tc /Leading 349 1 i (x ) Tj q endstream 0.271 Tc 1.005 0 0 1.015 45.168 53.449 cm /ProcSet[/PDF/Text] /Type /XObject q 0.458 0 0 RG endstream Q /Resources<< /Resources<< Q /Length 65 Q /Meta412 Do q /ProcSet[/PDF] q /Meta383 Do ET 1.007 0 0 1.007 45.168 813.037 cm /Type /XObject /Matrix [1 0 0 1 0 0] 0.564 G /F3 12.131 Tf 1.502 5.203 TD /FormType 1 /Type /XObject 1.007 0 0 1.006 411.035 510.406 cm 15.731 5.336 TD 1 i stream /Subtype /Form Q 0 G /FormType 1 0 g /Font << BT 1 i >> /FontDescriptor 10 0 R >> Thrice a number decreased by 5 exceeds twice the number by 1. /Font << q /Subtype /Form endstream Q >> << endobj /Type /XObject endobj /Leading 349 /F3 17 0 R 320 0 obj (x) Tj /F3 17 0 R /FormType 1 In humans, testosterone plays a key role in the development of male reproductive tissues such as testes and prostate, as well as promoting secondary sexual characteristics such as increased muscle and bone mass, and the growth of body hair. 2 0 obj /Resources<< 0 g /Meta267 Do 0 g /F1 12.131 Tf q /Length 16 >> >> 1.502 5.203 TD /F3 12.131 Tf /BBox [0 0 88.214 16.44] /Meta36 Do 1 i endobj /Type /XObject stream q /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] BT 0 5.203 TD 6.746 5.203 TD /Matrix [1 0 0 1 0 0] /I0 Do /Subtype /Form ET >> 1.014 0 0 1.007 251.439 583.429 cm /Type /XObject /Meta333 Do Q /Meta274 Do 30.699 5.203 TD /FormType 1 Q 1.007 0 0 1.007 271.012 636.879 cm /Resources<< 1.007 0 0 1.007 551.058 636.879 cm >> /Meta139 Do /ProcSet[/PDF/Text] 0.737 w /Meta153 Do 1.007 0 0 1.006 130.989 690.329 cm /Type /XObject stream Q q 0 g >> 0 G q 1 i 1 i 67 0 obj ET q 252 0 obj 0.68 Tc 369 0 obj /FormType 1 1 i /F3 12.131 Tf stream 1 i /Meta97 111 0 R /Meta236 250 0 R 21.713 20.154 l q BT q endstream >> Want to see the full answer? q /BBox [0 0 30.642 16.44] Q endstream 1 i q 0.175 Tc /FormType 1 Q /F1 12.131 Tf ET stream endobj endobj Q /Matrix [1 0 0 1 0 0] /F1 7 0 R 1 i /Meta331 345 0 R /Resources<< endobj /Subtype /Form 1.007 0 0 1.007 67.753 293.596 cm /F3 12.131 Tf Q %PDF-1.4 /Type /XObject << Q 1.014 0 0 1.006 111.416 437.384 cm stream Q /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] Q 1.014 0 0 1.007 111.416 583.429 cm Q Q 1 i 1.005 0 0 1.007 102.382 400.496 cm /Type /XObject endobj << /ProcSet[/PDF] >> endstream /Resources<< /Matrix [1 0 0 1 0 0] Q q /F3 17 0 R Q /Meta244 258 0 R /Meta21 32 0 R /Meta186 200 0 R stream q q stream q >> q /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] 0 g q 20.21 5.203 TD Q >> << /BBox [0 0 88.214 35.886] 1.014 0 0 1.007 531.485 383.934 cm /Meta229 243 0 R /Matrix [1 0 0 1 0 0] Q 1 g Q /Font << 87 0 obj >> /Meta217 Do 0 g /Matrix [1 0 0 1 0 0] 0 G /Subtype /Form /BBox [0 0 88.214 16.44] /ProcSet[/PDF/Text] /Length 16 >> >> >> [4] One half of a number decreased by fourteen is twenty-one 1.007 0 0 1.007 411.035 277.035 cm /Meta421 Do /ProcSet[/PDF/Text] endobj (-8) Tj 0 w endobj /F1 7 0 R 150 0 obj /Subtype /Form /ProcSet[/PDF/Text] 0 5.203 TD ET 159) n decreased by 28 is equal to 48 160) the difference of m and 27 is 34 161) a number decreased by 9 is 23 162) 13 less than w is equal to 35 163) the difference of a number and 22 is equal to 34 164) a number decreased by 27 is equal to 29 165) the difference of r and 20 is 37-6-You may use this math worksheet as long as you help someone . q endstream /Length 54 q q q q 1 i q q endobj ET >> q endstream /Font << endobj stream endstream endobj /Length 65 /Meta232 246 0 R 0 G /Subtype /Form 95 0 obj endstream >> Q [( and )-20(the product of )-15(a number a)-16(nd )] TJ /BBox [0 0 88.214 35.886] /F3 17 0 R /Matrix [1 0 0 1 0 0] 0.786 Tc Q /Type /XObject /Matrix [1 0 0 1 0 0] /Meta397 413 0 R Q 0.458 0 0 RG /StemH 94 endstream 1 g Q endstream Q /Type /XObject (\)) Tj endstream q Q /Meta302 316 0 R /Subtype /Form /F3 17 0 R /BBox [0 0 88.214 16.44] /Type /XObject /Meta166 Do 1 i 1 i q /XObject << << Q /Type /XObject endobj /Matrix [1 0 0 1 0 0] Thrice a number decreased by 5 exceeds twice the number by a unit. >> 392 0 obj ET Answer provided by our tutors. q q endstream /Meta249 Do /Resources<< >> endstream /Font << /BBox [0 0 30.642 16.44] 355 0 obj 20.21 5.203 TD stream >> q Q << q /BBox [0 0 30.642 16.44] 1.005 0 0 1.007 102.382 653.441 cm 0.369 Tc Q /Length 16 /Type /XObject q find what is x and check it 3x+2/5 - 2x-1/6 = 2/15 pa help po need ko lng po True or False: Let a & b be any elements of S, the set of natural numbers. 1 i 0.838 Tc /Meta262 276 0 R (3) Tj 0 g In addition, testosterone in both sexes is involved in health and well-being . 176 0 obj /ProcSet[/PDF] Q >> endobj Phrase : Expression : 4 times some number : 4x: twice a number : 2y : one-third of some number : the product of a number and 12 : 12w: Some examples of common phrases and corresponding . /Length 87 /Type /XObject 316 0 obj /Type /XObject /F1 12.131 Tf 0 w /F3 17 0 R For the lesson, he grabs a glass container shaped like a rectan Q 1 g 1 i /Length 59 Find the number. q (-9) Tj endstream endstream endobj BT >> /Length 59 1 i 1.007 0 0 1.007 130.989 636.879 cm >> q q 1 i << 1.007 0 0 1.006 551.058 836.374 cm /F3 12.131 Tf Q /Type /XObject /F3 17 0 R q 1 i /Subtype /Form /Matrix [1 0 0 1 0 0] Q q q endstream << /ProcSet[/PDF] >> >> >> 0.838 Tc endobj /Resources<< 200 0 obj /Resources<< Q stream 2.238 5.203 TD 0 g /Font << stream 0 5.336 TD /Subtype /Form stream /F3 17 0 R /Meta348 Do Q stream q q /Matrix [1 0 0 1 0 0] (9) Tj /Length 69 Q /Type /XObject 1.007 0 0 1.007 271.012 450.181 cm /BBox [0 0 15.59 16.44] See Solution. /Matrix [1 0 0 1 0 0] >> /FormType 1 0.51 Tc /Type /XObject 0 G Q /Matrix [1 0 0 1 0 0] 1.005 0 0 1.007 79.798 713.666 cm /F3 12.131 Tf To find: The. 33 0 obj /Length 69 Q 0 5.203 TD Q /Length 54 q q 1 g /Type /XObject Q >> Q /I0 Do /FormType 1 /Length 69 74 0 obj 1 i 1 i /Type /XObject 1 i /Meta1 Do >> 1.007 0 0 1.007 654.946 872.509 cm stream /Meta402 418 0 R /ProcSet[/PDF/Text] 1 i >> the ratio of a number and 4: x/4: the quotient of a and b: a/b: five decreased by t: 5-t: 3 less than 5 times a number: 5x-3: 6 years younger than Ann, Ann's age =a: a-6: three . 1.014 0 0 1.006 391.462 836.374 cm 0.737 w /Subtype /Form /F3 12.131 Tf q endstream ET 1 i Q << 0 G /Font << >> >> q 0 g We are asked to find the number, so, we could assign the number as "x". ET /Meta37 50 0 R BT /Type /XObject 1 i 0 G /FormType 1 0.838 Tc Q Q /FormType 1 0.564 G << q /BBox [0 0 30.642 16.44] Q q q Q /BBox [0 0 639.552 16.44] 0 5.203 TD 311 0 obj Q /Matrix [1 0 0 1 0 0] Q >> /Subtype /Form /BBox [0 0 639.552 16.44] Q 0.737 w /FormType 1 0.564 G 1 i 1 i >> endobj >> Aktual'nye voprosy Vol 10, No 3 (2020) 0.271 Tc 395 0 obj 0.737 w /BBox [0 0 88.214 16.44] 0 G /FormType 1 << 0 g q /F3 17 0 R 1 i /BBox [0 0 17.177 16.44] q /Type /Catalog Q Q /FormType 1 stream >> /FormType 1 q Let the 2nd number be y. 0.311 Tc 0 G >> /FormType 1 0 G 0 w Q ET 1.014 0 0 1.006 251.439 437.384 cm /FormType 1 0.564 G /Subtype /Form /Meta204 218 0 R 0.564 G stream Q ET q /Subtype /Form 0 g /Resources<< 0 g Q 0 g 183 0 obj /Font << Q /Meta322 Do /Meta99 113 0 R >> 0 g stream 337 0 obj 1 i >> 1 i >> /Meta420 436 0 R 1 g << (B\)) Tj << Q 1 g /Length 12 0.564 G 0.425 Tc /F4 36 0 R >> /ProcSet[/PDF/Text] /Meta160 Do /FormType 1 1.007 0 0 1.007 271.012 849.172 cm /Meta358 Do /BBox [0 0 15.59 16.44] /FormType 1 /Matrix [1 0 0 1 0 0] Q /ProcSet[/PDF/Text] 0.564 G 377 0 obj >> /Meta155 169 0 R q 89 0 obj 0.269 Tc q 1 i q endobj Q /F3 17 0 R stream /Matrix [1 0 0 1 0 0] 0 G 121 0 obj q 0 G Q Q /Meta114 128 0 R /FormType 1 /Length 12 /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] q Q ET BT q /Meta376 390 0 R 98 0 obj /FormType 1 /Type /XObject 0.564 G /Resources<< Q /Type /XObject >> 3.742 5.203 TD /Matrix [1 0 0 1 0 0] endobj /Matrix [1 0 0 1 0 0] ET >> 0 g /Type /XObject ( decreased by ) Tj q /ProcSet[/PDF/Text] q 170 0 obj 245 0 obj /Meta155 Do /BBox [0 0 17.177 16.44] Q << Q /BBox [0 0 88.214 16.44] /Resources<< Q >> q stream /F4 36 0 R 10 0 obj 1.014 0 0 1.007 391.462 330.484 cm q /XObject << Q /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] 1 i 0 G 0 w /ProcSet[/PDF/Text] Q There were x cookies at the beginning of a party. q 1 i q /Meta102 Do /Length 116 1 i /Subtype /Form q /FormType 1 /ProcSet[/PDF] 0.458 0 0 RG /Meta136 Do /F3 12.131 Tf /Subtype /Form q >> 92 0 obj 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